Integral Reversal: From 3 To 9 And Back

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Understanding the Properties of Definite Integrals

When we talk about definite integrals, one of the most fundamental properties to grasp is how reversing the limits of integration affects the result. This property is not just a mathematical quirk; it's a cornerstone that allows us to manipulate and solve integral problems more efficiently. Given that ∫39f(x)dx=247\int_3^9 f(x) d x=\frac{24}{7}, we are asked to find the value of ∫93f(z)dz\int_9^3 f(z) d z. At first glance, it might seem like a trick question or that we need to know the specific function f(x)f(x). However, the answer lies solely in understanding this key property of integrals. The variable used within the integral (whether it's xx, zz, or any other letter) is a dummy variable, meaning it doesn't affect the value of the definite integral. So, ∫39f(x)dx\int_3^9 f(x) d x is fundamentally the same as ∫39f(z)dz\int_3^9 f(z) d z. The crucial part here is the relationship between ∫abf(x)dx\int_a^b f(x) d x and ∫baf(x)dx\int_b^a f(x) d x. This relationship is defined by the property that states: ∫baf(x)dx=−∫abf(x)dx\int_b^a f(x) d x = -\int_a^b f(x) d x. This means that if you reverse the upper and lower limits of integration, the value of the integral is negated. It's like walking from point A to point B and then deciding to walk back from point B to point A; the distance covered is the same, but the direction of your displacement is reversed. In the context of integration, this reversal of direction corresponds to a change in sign. So, if the integral from 3 to 9 gives us a certain value, the integral from 9 back to 3 will yield the negative of that value.

The Inverse Relationship of Integral Limits

Let's delve deeper into why this inverse relationship holds true. The definite integral ∫abf(x)dx\int_a^b f(x) d x is defined as the limit of a Riemann sum. It represents the net signed area between the curve of f(x)f(x) and the x-axis from x=ax=a to x=bx=b. When we calculate this integral, we are essentially summing up infinitesimally small rectangular areas. The process moves from the lower limit (aa) to the upper limit (bb). If we consider the integral ∫baf(x)dx\int_b^a f(x) d x, we are still summing the same areas, but the direction of summation is reversed, from bb to aa. Imagine tracing a path on a number line. If you move from 3 to 9, you are moving in the positive direction. If you move from 9 to 3, you are moving in the negative direction. The integral is essentially accumulating values as we traverse this path. When the path is reversed, the accumulation process is also reversed, leading to a change in sign. This is directly derived from the fundamental theorem of calculus. If F(x)F(x) is an antiderivative of f(x)f(x), then ∫abf(x)dx=F(b)−F(a)\int_a^b f(x) d x = F(b) - F(a). Now, if we consider ∫baf(x)dx\int_b^a f(x) d x, using the same antiderivative F(x)F(x), we get ∫baf(x)dx=F(a)−F(b)\int_b^a f(x) d x = F(a) - F(b). Comparing the two, we can clearly see that F(a)−F(b)=−(F(b)−F(a))F(a) - F(b) = -(F(b) - F(a)). Therefore, ∫baf(x)dx=−∫abf(x)dx\int_b^a f(x) d x = -\int_a^b f(x) d x. This property is incredibly useful. It allows us to switch the order of integration limits if it simplifies a problem or if we are given information in a particular order and need it in the reverse order. The fact that the dummy variable can be changed (from xx to zz in our problem) is another important aspect. It signifies that the name of the variable we use to represent the function's input doesn't matter; it's the function itself and the interval over which we are integrating that determine the value. So, ∫39f(x)dx\int_3^9 f(x) d x and ∫39f(z)dz\int_3^9 f(z) d z are numerically identical. The question, therefore, boils down to applying the property of reversed integration limits to the given value.

Applying the Integral Property to Find the Solution

Now, let's apply this fundamental property directly to the problem at hand. We are given that ∫39f(x)dx=247\int_3^9 f(x) d x=\frac{24}{7}. We need to find the value of ∫93f(z)dz\int_9^3 f(z) d z. As we've established, the variable used in the integral does not change its value. Thus, ∫39f(x)dx=∫39f(z)dz=247\int_3^9 f(x) d x = \int_3^9 f(z) d z = \frac{24}{7}. The core of the problem is the reversal of the integration limits from 3 to 9 in the given integral to 9 to 3 in the integral we need to solve. Using the property ∫baf(x)dx=−∫abf(x)dx\int_b^a f(x) d x = -\int_a^b f(x) d x, we can directly substitute our values. In our case, a=3a=3 and b=9b=9. We are looking for ∫93f(z)dz\int_9^3 f(z) d z, which is equivalent to ∫93f(x)dx\int_9^3 f(x) d x because the variable is a dummy variable. Therefore, ∫93f(z)dz=−∫39f(z)dz\int_9^3 f(z) d z = -\int_3^9 f(z) d z. Since we know that ∫39f(z)dz=247\int_3^9 f(z) d z = \frac{24}{7}, we can conclude that ∫93f(z)dz=−247\int_9^3 f(z) d z = -\frac{24}{7}. The solution is straightforward once you understand the property of reversing integral limits. It's a direct application of a rule derived from the definition of the definite integral and the fundamental theorem of calculus. This property is not just theoretical; it's a practical tool in calculus that simplifies many integration problems and is essential for understanding more advanced concepts in mathematics and physics. The ability to manipulate integral limits can often be the key to solving complex problems or proving theorems. It highlights the elegance and interconnectedness of mathematical concepts, where a simple rule about reversing limits can unlock a solution. The fact that the variable name doesn't matter is also crucial; it emphasizes that the integral represents a value associated with the function over an interval, not with the specific representation of the function itself. This understanding allows us to move seamlessly between different notations and still arrive at the correct mathematical conclusion.

Conclusion: The Significance of Integral Properties

In conclusion, the problem of finding ∫93f(z)dz\int_9^3 f(z) d z given ∫39f(x)dx=247\int_3^9 f(x) d x=\frac{24}{7} is a direct test of understanding a fundamental property of definite integrals: reversing the limits of integration negates the value of the integral. The use of different variables (xx and zz) does not alter the outcome because they are dummy variables, representing the same underlying function over the same interval. Thus, ∫39f(x)dx=∫39f(z)dz\int_3^9 f(x) d x = \int_3^9 f(z) d z. By applying the property ∫baf(x)dx=−∫abf(x)dx\int_b^a f(x) d x = -\int_a^b f(x) d x, we find that ∫93f(z)dz=−∫39f(z)dz\int_9^3 f(z) d z = -\int_3^9 f(z) d z. Substituting the given value, we get ∫93f(z)dz=−247\int_9^3 f(z) d z = -\frac{24}{7}. This simple yet powerful property is a vital tool in calculus. It underscores the importance of mastering the basic rules and properties of integration, as they form the foundation for more advanced mathematical explorations. Understanding these properties allows mathematicians and students alike to solve problems more efficiently and with greater confidence. The concept of how the direction of integration affects the integral's value is intuitive when visualized as movement along a number line or as accumulating a quantity in one direction versus the opposite. For further exploration into the properties of definite integrals and calculus, you can refer to resources like the Khan Academy Calculus section or the Paul's Online Math Notes on Definite Integrals.